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Home > Curriculum Support > High School / Senior High > Physics > In Module 8, Test Question 8, if centripetal force depends on the inverse of r, why is the closer satellite the one that moves faster?
In Module 8, Test Question 8, if centripetal force depends on the inverse of r, why is the closer satellite the one that moves faster?
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You have to set the gravitational force equal to the centripetal force to understand the relationship between the two satellites. After all, the gravitational force IS the centripetal force:

Fc = (msat)x(v)2/r

Fg = Gx(mearth)x(msat)/r2

Gx(mearth)x(msat)/r2= (msat)x(v)2/r

Gx(mearth)/r = v2

v = square root (Gx(mearth)/r)

This equation shows you that the smaller the r, the greater the v.

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